Lemons and Oranges

Steffi, Emma and Amelia from Girton Glebe Primary School near Cambridge. We think we have the answer:

What strategy did the girls use to arrive at that answer? They explain:

That last point is very important! All the people who wrote in agree with the girls. But Luke shows his calculations to prove to us that there could be more than one possible answer. Do you agree with Luke?

Pupils at Alice Smith International School in Kuala Lumpur, Malaysia also worked on the Oranges and Lemons problem. They agree with Luke. One of the pupils, Kevin, shows all of the possibilities. They prove that there are in fact two possibilities but that there are no more.

What they already know:

To make it easy to read the answers, the pupils use a table:

To show how they arrived at each of these answers, here are the calculations:

1. $130$g + ($87$g $\times$ $2$) $87$g is max weight for Lemons = $304$g
2. ($130$g $\times$ $2$) + ($87$g $\times$ $4$) = $608$g
3. ($130$g $\times$ $3$) + ($87$g $\times$ $6$) = $912$g
4. ($130$g $\times$ $4$) + ($60$g $\times$ $8$) = $1000$g or $1$kg
5. ($130$g $\times$ $5$) + ($35$g $\times$ $10$) = $1000$g or $1$kg
6. ($130$g $\times$ $6$) = $780$g. $1000$g - $780$g = $220$g. $220$g divided by $12$ is $18.3$ recurring. It isn't a whole number.
7. $130$g $\times$ $7$ = $910$g. $1000$g - $910$g = $90$g. $90$ divided by $14$ equals $6.428571429$. It isn't a whole number.
8. $130$g $\times$ $8$ = $1040$g. It is more than $1000$g or $1$kg