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1$^3$=1, 2$^3$=8, 3$^3$=27, 4$^3$=64, 5$^3$ is more than 100
1 across is 27 or 64
1 across | 1 down | 3 across |
---|---|---|
27 | 26 | 64 |
64 | 63 | no cube begins with 3 |
Make a set of numbers that use all the digits from 1 to 9, once and once only. Add them up. The result is divisible by 9. Add each of the digits in the new number. What is their sum? Now try some other possibilities for yourself!
15 = 7 + 8 and 10 = 1 + 2 + 3 + 4. Can you say which numbers can be expressed as the sum of two or more consecutive integers?