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Plenty of Pens

Age 7 to 11
Challenge Level Yellow star
Primary curriculum
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Adrian has worked out this problem very efficiently:

No of pencils $= x$
No of pens $= 4x$

Spent on pencils $= 10x$
Spent on pens $= 4x \times15 = 60x$
Total spent $= 10x + 60x = 70x$

$70x = 250 - 40$
$70x = 210$
$x = 210 / 70 = 3$

Therefore no of pencils $= 3$
No of pens $= 3 \times4 = 12$

Pupils at Moorfield Juniors, including Emma, approached it slightly differently:

We worked this out by taking 40p from £2.50 which is 2.10 then using trial and error.
It was easy because there aren't many low numbers in the 4 times table.
The answer is 12 pens which equals £1.80. 12 divided by 4 = 3 so there are 3 pencils which equals 30p.
£1.80+30p= £2.10.


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The NRICH Project aims to enrich the mathematical experiences of all learners. To support this aim, members of the NRICH team work in a wide range of capacities, including providing professional development for teachers wishing to embed rich mathematical tasks into everyday classroom practice.

NRICH is part of the family of activities in the Millennium Mathematics Project.

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