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Isometric Rhombuses

Age 11 to 14
ShortChallenge Level Yellow star
Secondary curriculum
  • Problem
  • Solutions


There are a number of different ways of solving this problem.

Directions

The number of vertical rhombi can be seen by looking at the possible positions of the top triangle. The following six rhombi are then apparrent.

The problem has rotational symmetry, so the other two directions will also give six rhombi each.

This means that the total number of rhombi is $3 \times 6 = 18$.


Interior Edges

Each rhombus that is formed has exactly one of the interior edges (marked in red) contained within it. Moreover, each interior edge corresponds to one rhombus, consisting of the triangles on either side. There are $18$ interior edges, so $18$ rhombi that can be formed.





Double-counting

For each of the small triangles, the number of rhombi that contain it can be counted, as shown in the diagram on the right. However, this counts each rhombus twice (once for each triangle it contains). Therefore the total obtained ($36$) must be halved, giving a total of $18$ rhombi.

This problem is taken from the UKMT Mathematical Challenges.
You can find more short problems, arranged by curriculum topic, in our short problems collection.

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The NRICH Project aims to enrich the mathematical experiences of all learners. To support this aim, members of the NRICH team work in a wide range of capacities, including providing professional development for teachers wishing to embed rich mathematical tasks into everyday classroom practice.

NRICH is part of the family of activities in the Millennium Mathematics Project.

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