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a | 45a | Square? |
---|---|---|
1 | 45 | No |
2 | 90 | No |
3 | 135 | No |
4 | 180 | No |
5 | 225 | Yes: 15^2 = 225 |
This shows that the smallest possible number would be 5.
Alternatively, for 45a to be a square number, each of its prime factors must be raised to an even power. Since 45 = 3^2\times 5 as a product of prime factors, the only prime factor not raised to an even power is 5. Therefore the smallest value of a that makes this a square must be 5.
An investigation involving adding and subtracting sets of consecutive numbers. Lots to find out, lots to explore.
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