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Answer: $1 048 576$
Using powers
$2^{10}$ kilobytes in $1$ megabyte, and $2^{10}$ bytes in each of those $2^{10}$ kilobytes
So $2^{10}\times2^{10}$ bytes in $1$ megabyte.
$2^{10}\times2^{10}=2^{10+10}=2^{20}=1 048 576$, so there are $1 048 576$ (not $1 000 000$) bytes in a megabyte.
Using normal numbers
$2^{10}=1024$
$1024$ kilobytes in $1$ megabyte, and $1024$ bytes in each of those $1024$ kilobytes
So $1024\times1024$ bytes in $1$ megabyte.
$1024\times1024=1 048 576$, so there are $1 048 576$ (not $1 000 000$) bytes in a megabyte.
Megabytes and Kilobytes
Age 14 to 16
ShortChallenge Level 
Answer: $1 048 576$
Using powers
$2^{10}$ kilobytes in $1$ megabyte, and $2^{10}$ bytes in each of those $2^{10}$ kilobytes
So $2^{10}\times2^{10}$ bytes in $1$ megabyte.
$2^{10}\times2^{10}=2^{10+10}=2^{20}=1 048 576$, so there are $1 048 576$ (not $1 000 000$) bytes in a megabyte.
Using normal numbers
$2^{10}=1024$
$1024$ kilobytes in $1$ megabyte, and $1024$ bytes in each of those $1024$ kilobytes
So $1024\times1024$ bytes in $1$ megabyte.
$1024\times1024=1 048 576$, so there are $1 048 576$ (not $1 000 000$) bytes in a megabyte.
You can find more short problems, arranged by curriculum topic, in our short problems collection.
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