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Backwards Laps

Age 14 to 16
ShortChallenge Level Yellow starYellow starYellow star
Secondary curriculum
  • Problem
  • Solutions

Answer: 40 seconds

Using proportion
In 24 seconds:
 
Chris runs $\frac{24}{60}=\frac{2}{5}$ of a lap in 24 seconds
Sophie runs $1-\frac25=\frac{3}{5}$ of a lap in 24 seconds
                               $\frac{1}{5}$ of a lap in 24$\div$3 = 8 seconds
                             1 whole lap in 8$\times$5 = 40 seconds

OR
Chris runs $\frac25$ of a lap while Sophie runs $\frac35$ of a lap
$\therefore$ the distances they run in a fixed time are in the ratio $2:3$
$\therefore$ the times they take to run a fixed distance are in the ratio $3:2$
$3:2$ is equivalent to $60:40$



Using a Travel Diagram
The diagram below shows time horizontally and distance vertically, with lines sloping in opposite directions for Sophie's journey and Chris' journey, because they run in opposite directions.

They begin one full lap apart, which is actually when they are in the same place, and their paths cross again after 24 seconds.

 

The triangles coloured yellow in the diagram below are congruent, because of the symmetry in the diagram.
 

So, using scale factors within the triangles, $\dfrac{x}{24}=\dfrac{60}{36}\Rightarrow x=\dfrac{60}{36}\times24=40$
Or using scale factors between the triangles, $\dfrac{x}{60}=\dfrac{24}{36}\Rightarrow x=\dfrac{24}{36}\times60 = 40$

So Sophie runs a lap in 40 seconds.
 
You can find more short problems, arranged by curriculum topic, in our short problems collection.

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The NRICH Project aims to enrich the mathematical experiences of all learners. To support this aim, members of the NRICH team work in a wide range of capacities, including providing professional development for teachers wishing to embed rich mathematical tasks into everyday classroom practice.

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