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Divisible by 55

Age 11 to 14
ShortChallenge Level Yellow starYellow starYellow star
Secondary curriculum
  • Problem
  • Solutions

Answer: $a$ = 6 and $b = 5$ or $a$ = 1 and $b$ = 0


Multiples of 5 and 11 
55 = 5$\times$11

227569$ab$ is a multiple of 5 $\therefore b$ must be 5 or 0. 

If $b$ = 5,
 
remainder when 1$a$ is divided by 11 must be 5
$\therefore a$ = 6


If $b$ = 0,
 
remainder when 1$a$ is divided by 11 must be 0
$\therefore a$ = 1





Considering multiples of 55
We can look for multiples of 55 that are close to 22756900

Divide by 55/find a nearby multiple
55 $\times$ 4 = 220          22000000 is a multiple of 55
                          +     550000
                              22550000 is also a multiple of 55
55 $\times$ 3 = 165      +     165000
                              22715000
55 $\times$ 5 = 275       +      27500
                              22742500
55 $\times$ 2 = 110       +      11000
                              22753500
55 $\times$ 6 = 330       +        3300
                              22756800

Close multiples of 55:
22756800
22756855
22756910 ($a$ = 1 and $b$ = 0)
22756965 ($a$ = 6 and $b$ = 5)





You can find more short problems, arranged by curriculum topic, in our short problems collection.

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The NRICH Project aims to enrich the mathematical experiences of all learners. To support this aim, members of the NRICH team work in a wide range of capacities, including providing professional development for teachers wishing to embed rich mathematical tasks into everyday classroom practice.

NRICH is part of the family of activities in the Millennium Mathematics Project.

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