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Answer: 9 (so the number is 12349678)
Using division
The number is divisible by 11 so there must have been a remainder of 8 to give 88
___7 gives a remainder of 8
107 = 99 + 8
___6 gives a remainder of 10
Using place value and algebra
Missing Digit
Age 11 to 14
ShortChallenge Level 
Answer: 9 (so the number is 12349678)
Using division
The number is divisible by 11 so there must have been a remainder of 8 to give 88
___7 gives a remainder of 8
107 = 99 + 8
___6 gives a remainder of 10
76 = 66 + 10
2__ gives a remainder of 7
22 + 7 = 29
9 is missing
Using a divisibility test
A test for divisibility by 11 is to add alternate digits:
2__ gives a remainder of 7
22 + 7 = 29
9 is missing
Using a divisibility test
A test for divisibility by 11 is to add alternate digits:
1 + 3 + * + 7 = 11 + *; 2 + 4 + 6 + 8 = 20.
If the original number is a multiple of 11 then these two totals will be the same or will differ by a multiple of 11. In this case, 11 + * = 20 gives * = 9.
Using place value and algebra
1234*678 = 12340678 + 1000* = (11 x 1121879 +9) + 11 x 90* + 10*
and hence is divisible by 11 if and only if 10* + 9 is divisible by 11. So * = 9.
This problem is taken from the UKMT Mathematical Challenges.
You can find more short problems, arranged by curriculum topic, in our short problems collection.
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