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Answer: 9.09090...%
Using scale factors
Area is unchanged so ?% of 110% = 100%
$$\begin{align} \tfrac{?}{100}\times110 &= 100\\
?\times110&=10000\\
?\times11&=1000\\
? &= \tfrac{1000}{11} \text{ or } 90.90909...\end{align}$$ So the width is decreased by $100-90.90909...=9.090909...\text{ or }\frac{100}{11}=9\frac1{11}$
Using algebra
The area of the original rectangle was $wb$
The area of the altered rectangle is $pw \times 1.1b$
Since the two areas are equal,
$1.1 pwb = wb$
so
$1.1 p = 1$
so $p = \frac{1}{1.1} = \frac{10}{11}$
So the width is $\frac{10}{11}$ of its original value, so it has been decreased by $\frac1{11}$, which as a percentage is $9$ and $\frac1{11}\%$, or $9.09\%$ to 2.d.p.
Equal circles can be arranged so that each circle touches four or six others. What percentage of the plane is covered by circles in each packing pattern? ...
Prove that the shaded area of the semicircle is equal to the area of the inner circle.