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There are many solutions to this problem. Here is one correct solution received from a student at West Flegg Middle School in Norfolk.
Dee | Dum |
48 | 28 |
32 | 44 |
54 | 22 |
18 | 58 |
61.50 | 14.50 |
20.50 | 55.50 |
39 | 37 |
38 | 38 |
Hence, they share 76 pounds between them.
Year 5 pupils at Sutton High School also found a couple of solutions.
Ewan, from King Edward VII School in Sheffield, used algebra to make sure he found all the possible solutions.
DUM | DEE |
$x$ | $y$ |
$x+\frac{1}{3}y$ | $\frac{2}{3}y$ |
$\frac{1}{2}x+\frac{1}{6}y$ | $\frac{1}{2}x+\frac{5}{6}y$ |
$\frac{5}{6}x+\frac{13}{8}y$ | $\frac{1}{6}x+\frac{5}{8}y$ |
$\frac{5}{24}x+\frac{13}{72}y$ | $\frac{19}{24}x+\frac{59}{72}y$ |
$\frac{53}{72}x+\frac{157}{216}y$ | $\frac{19}{72}x+\frac{59}{216}y$ |
$\frac{53}{108}x+\frac{157}{324}y$ | $\frac{55}{108}x+\frac{167}{324}y$ |
$x$ | $y$ | Total |
$3$ | $63$ | $66$ |
$8$ | $60$ | $68$ |
$13$ | $57$ | $70$ |
$18$ | $54$ | $72$ |
$23$ | $51$ | $74$ |
$28$ | $48$ | $76$ |
$33$ | $45$ | $78$ |
$38$ | $42$ | $80$ |
The sum of the numbers 4 and 1 [1/3] is the same as the product of 4 and 1 [1/3]; that is to say 4 + 1 [1/3] = 4 � 1 [1/3]. What other numbers have the sum equal to the product and can this be so for any whole numbers?
Find some examples of pairs of numbers such that their sum is a factor of their product. eg. 4 + 12 = 16 and 4 × 12 = 48 and 16 is a factor of 48.
When I type a sequence of letters my calculator gives the product of all the numbers in the corresponding memories. What numbers should I store so that when I type 'ONE' it returns 1, and when I type 'TWO' it returns 2, and so on.