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78 x 78 = 6084
80 x 80 = 6400
92 x 92 = 8464
Allan has cracked yet another tough nut but others may have further comments to make about this one.
The numbers are the squares of 33 and 99, they are 1089 and 9801.
First, I noticed that multiples of 11, when reversed, are still
multiples of 11, like 143, which becomes 341, when reversed, which
is divisible by 11.
Next, I found that some multiples of 11 x 11, which is 121, when
reversed, are also divisible by 121.
Then I found that multiples of 9, when reversed, are still
divisible by 9.
The number 1089, which is the lowest common multiple of 121 and 9,
when multipled by 9, gives the number 9801.
The square root of 1089 is 33, and the square root of 9801 is
99.
Make a set of numbers that use all the digits from 1 to 9, once and once only. Add them up. The result is divisible by 9. Add each of the digits in the new number. What is their sum? Now try some other possibilities for yourself!
Choose any 3 digits and make a 6 digit number by repeating the 3 digits in the same order (e.g. 594594). Explain why whatever digits you choose the number will always be divisible by 7, 11 and 13.