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How about the combination
1, 2, 3, 4? Of course they have exchanges cards with one another. 1, 5, 6, 7? Yes of course, they have.
1, 8, 9, 10? Sure they did!
1, 11, 12, 13? Yes!
1, 14, 15, 16? Yes!
1, 17, 18, 19? Yes too!
1, 20, 21, 22?
1, 23, 24, 25?
1, 26, 27, 28?
1, 29, 30, 2?
Now comes the conclusion: student number 1 has exchanged cards with everyone else in the class.
How about student number 2? Using the same method, you can find out that he or she has exchanged cards with everyone else as well.
And so did number 3, 4, and everyone else in the class.
The truth is, everyone (30 students) had exchanged cards with everyone else.
Further question: What if, in each subset of 4 students, at least one (but not necessarily all four) had exchanged cards with the other three?
Suppose you had to begin the never ending task of writing out the natural numbers: 1, 2, 3, 4, 5.... and so on. What would be the 1000th digit you would write down.
How many ways can you write the word EUROMATHS by starting at the top left hand corner and taking the next letter by stepping one step down or one step to the right in a 5x5 array?
A political commentator summed up an election result. Given that there were just four candidates and that the figures quoted were exact find the number of votes polled for each candidate.