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Answer: 2^{13}
\begin{align} &\left(64 \text{ men }+64\text{ women}\right)\times 64\text{p}\\ 2^3 = 8,\hspace{2mm} 2^4 = 16,\hspace{2mm} &2^5 = 32,\hspace{2mm} 2^6 = 64\\ &\left(\hspace{6mm}2^6 \hspace{8mm}+\hspace{8mm} 2^6 \hspace{6mm}\right)\times 2^6\\ =&\left(2^6\times2\right)\times2^6\\ =&2^6\times2^1\times2^6\\ =&2^{13}\end{align}
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Age 11 to 14
ShortChallenge Level 
Answer: 2^{13}
\begin{align} &\left(64 \text{ men }+64\text{ women}\right)\times 64\text{p}\\ 2^3 = 8,\hspace{2mm} 2^4 = 16,\hspace{2mm} &2^5 = 32,\hspace{2mm} 2^6 = 64\\ &\left(\hspace{6mm}2^6 \hspace{8mm}+\hspace{8mm} 2^6 \hspace{6mm}\right)\times 2^6\\ =&\left(2^6\times2\right)\times2^6\\ =&2^6\times2^1\times2^6\\ =&2^{13}\end{align}
This problem is taken from the UKMT Mathematical Challenges.
You can find more short problems, arranged by curriculum topic, in our short problems collection.
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