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We are given:
We want to find the bearing of the School from the Church, which is the green angle marked on the diagram. We can use the fact that the angles in a triangle sum to $180^\circ$ to mark in some other angles
We know the triangle linking the three buildings is isosceles, so the two missing angles are equal, so are both $30^\circ$.So:
So the green angle is $180^\circ+30^\circ = 210^\circ$, so the bearing of the School from the Church is $210$.
Overbearing
Age 11 to 14
ShortChallenge Level 
We are given:
We want to find the bearing of the School from the Church, which is the green angle marked on the diagram. We can use the fact that the angles in a triangle sum to $180^\circ$ to mark in some other angles
We know the triangle linking the three buildings is isosceles, so the two missing angles are equal, so are both $30^\circ$.So:
So the green angle is $180^\circ+30^\circ = 210^\circ$, so the bearing of the School from the Church is $210$.
This problem is taken from the UKMT Mathematical Challenges.
You can find more short problems, arranged by curriculum topic, in our short problems collection.
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