100 = 50\times2\times1\times1 not all different
= 10\times5\times2\times1 good! Sum = 18
Is there another way?
Factors of 100 not used: 4, 20, 25
100 = 4\times25\times1\times1 not all different
= 4\times5\times5\times1 not all different. Cannot use 4
= 25\times2\times2\times1 not all different. Cannot use 25
100 = 20\times5\times1\times1 not all different. Cannot use 20
Make a set of numbers that use all the digits from 1 to 9, once and
once only. Add them up. The result is divisible by 9. Add each of
the digits in the new number. What is their sum? Now try some other
possibilities for yourself!