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Converging Means

Age 14 to 16
Challenge Level Yellow starYellow star
  • Problem
  • Student Solutions
Take any two positive numbers and call the larger one $a_1$ and smaller $b_1$. Calculate the arithmetic mean of the two numbers and call this $a_2$, where: $$a_2 = (a_1+ b_1)/2.$$Calculate the geometric mean of $a_1$ and $b_1$ and call this $ b_2$ so that: $$b_2 = \sqrt{(a_1b_1)}.$$ Suppose you start with 3 and 12, then the arithmetic mean is 7.5 and the geometric mean is 6.

Repeat the calculations to generate a sequence of arithmetic means $a_1$, $a_2$, $a_3$, ... and a sequence of geometric means $b_1$, $b_2$, $b_3$, ... where $$a_{n+1} = (a_n+ b_n)/2,$$ $$b_{n+1} = \sqrt{(a_nb_n)}.$$In the example given $$a_2 = 6.75,$$ $$b_2 = \sqrt{(45)}= 6.708\; \mbox{to 3 decimal places}.$$Calculate the first 5 terms of each sequence and mark them on a number line. Calculate a few more terms and make a note of what happens to the two sequences.

Now repeat the same calculations starting with different choices of positive values for $a_1$ and $b_1$. You should notice the same behaviour of the two sequences whatever starting values you choose. Describe and explain this behaviour.

You may like to write a short program for a calculator or computer to calculate the sequences and if so you should send in your program with your solution.

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The NRICH Project aims to enrich the mathematical experiences of all learners. To support this aim, members of the NRICH team work in a wide range of capacities, including providing professional development for teachers wishing to embed rich mathematical tasks into everyday classroom practice.

NRICH is part of the family of activities in the Millennium Mathematics Project.

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