After geometric series, this is one of the simplest infinite series with finite sum, all of whose terms are positive. This geometric demonstration of the result requires students to continue a pattern and to use several steps of reasoning to deduce that the sum is bounded by 2. Summing infinite geometric series also play an important role in the this proof, so this could be used to
show an application of them in a larger proof. (It would be useful for students to be able to sum $\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\cdots$ before tackling this problem.)
The exact value of this sum was first discovered by Euler after having defeated many other great mathematicians of the time: it is $\frac{\pi^2}{6}$.
Possible approach
Students might consider the problem Harmonically before or after this problem, which shows a start contrast between similar-looking series, one of which converges and the other diverges.
For this problem, students could be asked to make a prediction about the sum of the series before being shown the image. They could then be given the image and asked to work out how it relates to the sum, and what they can deduce from it.
A more challenging variant would be to ask students if they can show geometrically that the series sums to less than 2 without giving them an image to work with.
Key questions
What are the side lengths of the blue squares?
How does the image continue?
Will all of the necessary blue squares fit in the two large squares?
Possible extension
What can you say about the sum of the series $\dfrac{1}{1^s}+\dfrac{1}{2^s}+\dfrac{1}{3^s}+\dfrac{1}{4^s}+\cdots$ if $s$ is a number other than 2?
Possible support
Students might need help identifying what they need to justify: in particular, they may not show that the squares fit in each row, and that all the rows fit inside the right-hand square.
Further exploration
One of the assignments on the STEP Support Programme, Assignment 24, has a warm-down problem which explores this sum a little further. A video showing a beautiful geometric argument has been made by 3Blue1Brown and is available here. Many other approaches to calculating the exact sum can be found online.