Let's say the operator changes $a_n$ to $a_{n'}$ where these are
any positive integers between 0 and 9. The condition the machine
doesn't find the error is that the new number is also a valid money
order number. So $a_n - a_{n'}\equiv 0 \hbox{ mod 9}$.
This can happen only when the operator changes 0 with 9 or 9 with 0
for any digit including the first one (which could be 0). In all
other cases the error will be found. Now I'll examine separately
the case of the check digit. The same rule holds for it too,
because I must look at the congruence mod 9, i.e. if there is an
error in the check digit it is not detected by the machine if 0 is
replaced by 9 or 9 by 0.
For an Airline Ticket, in order the machine does not find the
error, the difference between the numbers obtained omitting the
check digit, in the correct and in the miscopied form, must be a
multiple of 7. But, if the difference of two numbers differing only
in one digit is a multiple of 7, the numbers must differ by 7, 70,
700, 7000 ... and this means the difference of the two digits must
be 7. The machine will not find the error if the operator changes 0
with 7, 1 with 8 or 2 with 9, or 7 with 0, 8 with 1, 9 with 2. The
same is valid for the check digit too.
2. Transposing two adjacent digits
For the US Postal Service Money Order numbers the machine won't
find the error except transposing the check digit. The machine
doesn't find it because the addition is commutative.
For Airline Ticket numbers I work on the number omitting the check
digit. The miscopied number goes undetected when the remainders
after division of the numbers by 7 are the same that is when the
difference of the two numbers is a multiple of 7. Let the two
adjacent digits be a and b so the difference between the two
numbers is a power of 10 times 9(a - b). If this is a multiple of 7
then (a - b) is a multiple of 7. The error will be undetected if
the adjacent digits transposed are 0 and 7 or 1 and 8 or 2 and 9.
a) A four digit number (in base 10) aabb is a perfect square. Discuss ways of systematically finding this number.
(b) Prove that 11^{10}-1 is divisible by 100.