Or search by topic
If we take any 8 consecutive numbers: n, n+1, n+2, n+3, n+4, n+5, n+6, n+7
This means that the terms in x^2, in x, and the constant term must be split equally.
If we sum the squares of each of the eight consecutive numbers, and then halve the result, this will equal the sum of each of the four terms needed. So adding all the squares we have: n^2 + (n+1)^2 + (n+2)^2 + (n+3)^2 + (n+4)^2 (n+5)^2 + (n+6)^2 + (n+7)^2 =
Find the polynomial p(x) with integer coefficients such that one solution of the equation p(x)=0 is 1+\sqrt 2+\sqrt 3.
Find the exact values of x, y and a satisfying the following system of equations: 1/(a+1) = a - 1 x + y = 2a x = ay