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The total number they were playing with must be divisible by $3$.
The number of Ben's counters must initially be divisible by $3$, Jack's by $4$ and Emma's by $5$.
It might help to work out the maximum each could have started with -
e.g. Emma could not have started with $25$ counters. Can you work out why?
How many counters could each of them have started with?
Try some possible numbers.
Make a set of numbers that use all the digits from 1 to 9, once and once only. Add them up. The result is divisible by 9. Add each of the digits in the new number. What is their sum? Now try some other possibilities for yourself!
Take any pair of two digit numbers x=ab and y=cd where, without loss of generality, ab > cd . Form two 4 digit numbers r=abcd and s=cdab and calculate: {r^2 - s^2} /{x^2 - y^2}.