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The $n$th term of a sequence is given by the formula
$n^3 + 11n$.
Find the first four terms of the sequence given by this formula and the first term of the sequence which is bigger than one million.
Prove that all terms of the sequence are divisible by $6$.
In turn 4 people throw away three nuts from a pile and hide a quarter of the remainder finally leaving a multiple of 4 nuts. How many nuts were at the start?
Find the smallest numbers a, b, and c such that: a^2 = 2b^3 = 3c^5 What can you say about other solutions to this problem?