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You know what the area of the four parts must be.
Think about symmetrical drawings.
Can you draw three lines inside the circle in such a way that
they enclose an area which can be expanded or contracted to give
the required area?
The Solution section gives one possibility (see link above).
There are many other possibilities you could investigate.
Here is just one alternative line of approach you could
pursue:
The diagram shows another solution for 3 lines but the same
principle applies to any regular polygon. For an $n$-gon the angle
marked at the centre of the circle $C$ will be ${\pi \over n}$. As
$n$ gets larger the polygons will get smaller and the lines will
'radiate' out more like the spokes of a wheel.
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A and B are two points on a circle centre O. Tangents at A and B cut at C. CO cuts the circle at D. What is the relationship between areas of ADBO, ABO and ACBO?
By inscribing a circle in a square and then a square in a circle find an approximation to pi. By using a hexagon, can you improve on the approximation?