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This problem brings together some key ideas including the value of similar triangles, employing useful lines, some algebra and that problems can be solved even when information seems limited. The problem can be used to make sense of other people's mathematical arguments. The aim of bringing the three problems together is to encourage discussion about their links and connectedness and therefore investigate relationships between problems and problem-solving experiences.
This printable worksheet may be useful: Partly Circles.
The first problem is designed to draw attention to similar triangles and to see these learners need to add lines.
Present the problem and give time for reflection and then discussion. If ideas are not forthcoming suggest the addition of two lines (you might add them to the diagram without discussion) and then use of angles in the same segment. If necessary spend some time adding and removing pairs of lines talking about what is known about the triangles created:
Consider other ways of writing the result or substitute integers for three of the letters asking what the fourth must be (if a=$3$, b=$5$ and c=$6$ what must d be?)
The next two problems can be tackled in any order, and the images in Getting Started might help stimulate discussion.
Once solutions for all three problems are available spend time discussing connections learners can make and those that are worth drawing particular attention to.
What lines can you draw that highlight additional properties
Can you identify similar triangles?
What do the first and scond problems have in common?
How about the second and last problems?
Can you think of other problems where you have used similar ideas?
The largest square which fits into a circle is ABCD and EFGH is a square with G and H on the line CD and E and F on the circumference of the circle. Show that AB = 5EF. Similarly the largest equilateral triangle which fits into a circle is LMN and PQR is an equilateral triangle with P and Q on the line LM and R on the circumference of the circle. Show that LM = 3PQ
You are only given the three midpoints of the sides of a triangle. How can you construct the original triangle?