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In this case M = 5 and N = 3 so the number of ribbons is 1.
Therefore, if a square Celtic knot has side length x, the number of different ribbons will be x.
In this case x = 4 so the number of ribbons is 4.
The number of crossovers for a square Celtic knot is $$2x^2 - 2x$$ or $$2x (x - 1)$$
Students from Garden International School also worked on this problem. Here is what Kenn, Jong Woong, Jayme and Marana sent us.
Drawing Celtic Knots
Age 11 to 14
Challenge Level 
William from Barnton Community Primary School discovered that:
If there is a rectangular Celtic knot that is M by N then the
number of ribbons is the highest common factor of M and N.
In this case M = 5 and N = 3 so the number of ribbons is 1.
Therefore, if a square Celtic knot has side length x, the number of different ribbons will be x.
In this case x = 4 so the number of ribbons is 4.
The number of crossovers for a square Celtic knot is $$2x^2 - 2x$$ or $$2x (x - 1)$$
Students from Garden International School also worked on this problem. Here is what Kenn, Jong Woong, Jayme and Marana sent us.
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